The polar form of a complex number is another way of representing complex numbers. The form z = a+bi is the rectangular form of a complex number, where (a, b) are the rectangular coordinates. The polar form of a complex number is represented in terms of modulus and argument of the complex number. It is said Sir Isaac Newton was the one who developed 10 different coordinate systems, one among them being the polar coordinate system.
In this mini-lesson, we will get an overview of representing the polar form of complex numbers, the magnitude of complex numbers, the argument of the complex number, modulus of the complex number.
1. | What is Polar Form of Complex Numbers? |
2. | Representation of Polar Form of Complex Numbers |
3. | Conversion From Rectangular Form to Polar Form of Complex Number |
4. | Product of Polar Form of Complex Numbers |
5. | FAQs on Polar Form of Complex Numbers |
In polar form, complex numbers are represented as the combination of the modulus r and argument θ of the complex number. The polar form of a complex number z = x + iy with coordinates (x, y) is given as z = r cosθ + i r sinθ = r (cosθ + i sinθ). The polar form is represented with the help of polar coordinates of real and imaginary numbers in the coordinate system. Consider a complex number A = x + i y in a two-dimensional coordinate system:
In the figure above, we have cosθ = x/r; sinθ = y/r ⇒ x = rcosθ, y = rsinθ. Using Pythagoras theorem, we have r 2 = x 2 + y 2 and tanθ = y/x ⇒ r = √(x 2 + y 2 ) and θ = tan -1 (y/x).
The polar form of a complex number z = x + iy with coordinates (x, y) is given as z = r cosθ + i r sinθ = r (cosθ + i sinθ). The abbreviated polar form of a complex number is z = rcis θ, where r = √(x 2 + y 2 ) and θ = tan -1 (y/x). The components of polar form of a complex number are:
We write complex numbers in terms of the distance from the origin and a direction (or angle) from the positive horizontal axis. Polar coordinates are expressed as (r, θ). Polar form for a complex number z=a+bi is given by z = r cosθ + i r sinθ, where r = √(a 2 + b 2 ), a=r cosθ and b=r sinθ
Tips and Tricks:
The conversion of complex number z=a+bi from rectangular form to polar form is done using the formulas r = √(a 2 + b 2 ), θ = tan -1 (b / a). Consider the complex number z = - 2 + 2√3 i, and determine its magnitude and argument. We note that z lies in the second quadrant, as shown below:
Using Pythagoras Theorem, the distance of z from the origin, or the magnitude of z, is |z| = √((-2) 2 + (2√3) 2 ) = √(4+12) = √16 = 4. Now, let us calculate the angle between the line segment joining the origin to z (OP) and the positive real direction (ray OX). Note that the angle POX' is tan -1 (2√3/(-2)) = tan -1 (-√3) = -tan -1 (√3). Since the complex number lies in the second quadrant, the argument θ = - tan -1 (√3) + 180° = - 60° + 180° = 120°. So, the polar form of complex number z = - 2 + 2√3 i will be 4(cos120° + i sin120°)
Let us consider two complex numbers in polar form, z = r1(cos θ1 + i sin θ1), w = r2(cos θ2 + i sin θ2), Now, let us multiply the two complex numbers:
Related Topics to Polar Form of Complex Number
Important Notes on Polar Form of Complex Number
Example 1: The distance of point B from the origin is 4 units and the angle made with the positive x-axis is π/3. Find the polar coordinates of point B using the formula for the polar form of complex numbers. Solution: Distance of point B from the origin, r = 4 units Angle made with the positive x-axis, θ = π/3 The polar coordinates of complex number at point B are (4, π/3) Answer: Polar coordinates of complex number at point B are (4, π/3)
Example 2: Determine the modulus and argument of z = 1 + 6i using the formula for the polar form of complex numbers. Solution: Using the formula for modulus, we have |z| = √(1 2 + 6 2 ) = √(1 + 36) = √37 Since the real part and imaginary part of the complex number z = 1 + 6i are positive, z lies in the first quadrant. The argument of z is given by θ = tan -1 (6 / 1) = tan -1 6 = 80.54° Answer: The modulus and argument of z = 1 + 6i are √37 and 80.54°, respectively.
Example 3: Find the modulus and argument of z = 1 - 3i using the formula for the polar form of complex numbers. Solution: The modulus of z = 1 - 3i is |z| = √(1 2 + (-3) 2 ) = √(1+9) = √10 Now, since the real part is positive and the imaginary part is negative, z lies in the fourth quadrant. The angle θ is given by θ = tan -1 (-3 / 1) = -tan -1 (3) = -71.565° The significance of the minus sign is in the direction in which the angle needs to be measured. Answer: The modulus and argument of z = 1 - 3i are √10 and -71.565°, respectively.
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